This program asks the user to store the value of noOfRecords
and allocates the memory for the noOfRecords
structure variables dynamically using the malloc()
function.
Demonstrate the Dynamic Memory Allocation for Structure
#include <stdio.h>
#include <stdlib.h>
struct course {
int marks;
char subject[30];
};
int main() {
struct course *ptr;
int noOfRecords;
printf("Enter the number of records: ");
scanf("%d", &noOfRecords);
// Memory allocation for noOfRecords structures
ptr = (struct course *)malloc(noOfRecords * sizeof(struct course));
for (int i = 0; i < noOfRecords; ++i) {
printf("Enter subject and marks:\n");
scanf("%s %d", (ptr + i)->subject, &(ptr + i)->marks);
}
printf("Displaying Information:\n");
for (int i = 0; i < noOfRecords; ++i) {
printf("%s\t%d\n", (ptr + i)->subject, (ptr + i)->marks);
}
free(ptr);
return 0;
}
Output
Enter the number of records: 2 Enter subject and marks: Science 82 Enter subject and marks: DSA 73 Displaying Information: Science 82 DSA 73