The min()
method returns the minimum key-value pair in the dictionary.
Example
let studentsHeights = ["Sabby": 180.6, "Dabby": 170.3, "Cathy": 156]
// compare the values and return minimum key-value pair
let minimumHeight = studentsHeights.min { $0.value < $1.value }
print(minimumHeight!)
// Output: (key: "Cathy", value: 156.0)
min() Syntax
The syntax of the dictionary min()
method is:
dictionary.min {operator}
Here, dictionary is an object of the dictionary
class.
min() Parameters
The min()
method can take one parameter:
- operator - a closure that accepts a condition and returns a Bool value.
min() Return Value
The min()
method returns the minimum element of dictionary.
Note: If dictionary is empty, the method returns nil
.
Example 1: Swift dictionary min()
let fruitPrice = ["Grapes": 2.5, "Apricot": 3.5 , "Pear": 1.6]
// compares the values and return minimum key-value pair
let minimumPrice = fruitPrice.min { $0.value < $1.value }
print(minimumPrice!)
Output
(key: "Pear", value: 1.6)
In the above example, we have passed the closure to find the minimum key-value pair by comparing all the values in fruitPrice. Notice the closure definition,
{ $0.value < $1.value }
This is a short-hand closure that checks whether the first value of fruitPrice is less than the second value or not.
$0
and $1
is the shortcut to mean the first and second parameters passed into the closure.
Since the min()
method is optional, we have force unwrapped the optional using !
.
Example 2: Compare Keys and Return min Value
let fruitPrice = ["Grapes": 2.5, "Apricot": 3.5 , "Pear": 1.6]
// compares the keys and return minimum key-value pair
let minimumPrice = fruitPrice.min { $0.key < $1.key }
print(minimumPrice!)
Output
(key: "Apricot", value: 3.5)
Here, we have used the key
property to compare all the keys of the fruitPrice dictionary
{ $0.key < $1.key }