The fmod() function in C++ computes the floating point remainder of numerator/denominator (rounded towards zero).
fmod (x, y) = x - tquote * y
where tquote is truncated i.e. (rounded towards zero) result of x/y.
fmod() prototype [As of C++ 11 standard]
double fmod(double x, double y); float fmod(float x, float y); long double fmod(long double x, long double y); double fmod(Type1 x, Type2 y); // Additional overloads for other combinations of arithmetic types
The fmod() function takes a two arguments and returns a value of type double, float or long double type. This function is defined in <cmath> header file.
fmod() Parameters
- x: The value of numerator.
- y: The value of denominator.
fmod() Return value
The fmod() function returns the floating point remainder of x/y. If the denominator y is zero, fmod() returns NaN (Not a Number).
Example 1: How fmod() works in C++?
#include <iostream>
#include <cmath>
using namespace std;
int main()
{
double x = 7.5, y = 2.1;
double result = fmod(x, y);
cout << "Remainder of " << x << "/" << y << " = " << result << endl;
x = -17.50, y = 2.0;
result = fmod(x, y);
cout << "Remainder of " << x << "/" << y << " = " << result << endl;
return 0;
}
When you run the program, the output will be:
Remainder of 7.5/2.1 = 1.2 Remainder of -17.5/2 = -1.5
Example 2: fmod() function for arguments of different types
#include <iostream>
#include <cmath>
using namespace std;
int main()
{
double x = 12.19, result;
int y = -3;
result = fmod(x, y);
cout << "Remainder of " << x << "/" << y << " = " << result << endl;
y = 0;
result = fmod(x, y);
cout << "Remainder of " << x << "/" << y << " = " << result << endl;
return 0;
}
When you run the program, the output will be:
Remainder of 12.19/-3 = 0.19 Remainder of 12.19/0 = -nan
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